Question

Solve 5 to 11 sum with full solution​

Answer 1

Answer:

-1/2

${?}^{2}$

Answer 2

Step-by-step explanation:

$(5){x}^{a - b} \times {x}^{b - c} \times {x}^{c - a} = {x}^{a - b + b - c + c - a} \\ = {x}^{0} = 1$

$(7) {10}^{3x} = {100}^{9 } = > {10}^{3x} = { ({10}^{2} \:) ^{9} } \\ = > {10}^{3x} = {10}^{18} \\ = > 3x = 18 \\ = > x = \frac{18}{3} = 6 \\ therefore \: 8x = 8 \times 6 = 48$

$(9) \: {6}^{2} ( {6}^{ - 1 } \times {6}^{1} \times {6}^{ - 1} ) = \frac{ {6}^{2} }{6} \times \frac{6}{6} \\ = > 6 \times 1 = 6$

$(11)$

$(11)given \: x = 3 \: and \: y = - 6 \\ therefore \: { (\frac{x}{y} )}^{n} = {( \frac{3}{ - 6} )}^{n} = { (\frac{ - 1}{2} )}^{n}$