Math, asked by lakahanya54, 11 months ago

solve
5/x-1 + 1/y-2=2
6/x-1 + -3/y-2=1​

Answers

Answered by iTzMiSsTwinKle
8

Answer:

□X=4✔✔

□Y=5✔✔

Step-by-step explanation:

 \frac{5}{x - 1}  +  \frac{1}{y - 2}  = 2 -  -  -  -  - (1) \\  \frac{6}{x - 1}  +  \frac{ - 3}{y - 2}  = 1 -  -  -  -  - (2) \\ let \:  \frac{1}{x - 1}  = p -  -  -  -  - (3) \\  \:  \:  \:   \:  \: \frac{1}{x - 2}  = q -  -  -  -  - (4) \\ putting \: value \: of \: (3) \: and \: (4) \: in \: (1) \: and  \: (2) \: so \: we \: get \: \\ 5p + q = 2 \\ 5p = 2 - q \\ p =  \frac{2 - q}{5}  -  -  -  -  -  - (5) \\ again \\ 6p  - 3q = 1 \\ putting \: value \: of \: p \:  \\ 6 \times  (\frac{2 - q}{5})  - 3q = 1 \\  \frac{12 - 6q - 15q}{5}  = 1 \\  - 21q = 5 - 12 \\ q =   \frac{ - 7}{  - 21}  \\ q =  \frac{1}{3}  \\ putting \: value \: of \: q \: in \: (5) \\5 p = 2 -  \frac{1}{3}  \\ 5p =  \frac{5}{3}  \\ p =  \frac{1}{3}  \\ putting \: value \: of \: p \: and \: q \:  in \: (3) \: and \: (4) \: we \: get \\  \frac{1}{x - 1}  =  \frac{1}{3}  \\ x = 4 \\ again \\  \frac{1}{y - 2} =  \frac{1}{3}   \\ y = 5

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