Math, asked by falgunibhatt1806, 4 months ago

solve 5(x-2)+4(x+1)=3(x+5)​


Flaunt: @itzkinghere don't report good answers

Answers

Answered by navinnagda07
2

Answer:

5x-10+4x+4=3x+15

9x-6=3x+15

9x-3x=15+6

3x=21

x=21/3

x=7


falgunibhatt1806: what's your name
Answered by Flaunt
139

\sf\huge\bold{Solution}

\sf\longmapsto5(x - 2) + 4(x + 1) = 3(x + 5)

\sf\longmapsto5x - 10 + 4x + 4 = 3x + 15

\sf\longmapsto9x - 6 = 3x + 15

\sf\longmapsto9x - 3x = 15 + 6

\sf\longmapsto6x = 21

\sf\longmapsto \: x =  \dfrac{21}{6}  =  \dfrac{7}{2}

Check

Taking L.H.S

\sf\longmapsto5\bigg( \dfrac{7}{2}  - 2\bigg) + 4\bigg( \dfrac{7}{2}  + 1\bigg)

\sf\longmapsto5\bigg( \dfrac{7 - 4}{2} \bigg) + 4\bigg( \dfrac{7 + 2}{2}\bigg )

\sf\longmapsto5  \times  \dfrac{3}{2}  + 4 \times  \dfrac{9}{2}

\sf\longmapsto \dfrac{15}{2}  +  \dfrac{36}{2}  =  \dfrac{51}{2}

Taking R.H.S

\sf\longmapsto3\bigg( \dfrac{7}{2}  + 5\bigg)

\sf\longmapsto3\bigg( \dfrac{7 + 10}{2} \bigg)

\sf\longmapsto3\bigg( \dfrac{17}{2}\bigg )

\sf\longmapsto \dfrac{51}{2}


tannuverma1482005: thanks dear
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