Solve:
(5/x+y)-(2/x-y) = -1,
(15/x+y)+(7/x-y)=10
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Answered by
19
The given equations are:
(5/x+y)-(2/x-y) = -1, .....(i)
(15/x+y)+(7/x-y)=10.....(ii)
Taking (1/x+y)= u and (1/x-y) = v
So, the given equations can also be written as_
5u-2v = -1....(iii)
15u+7v = 10....(iv)
Multiplying equation (iii) by 3
So we get,
(5u-2v)×3=-1×3
⇒ 15 u - 6v = -3....(v)
15u+7v = 10....(vi)
Subtracting equation (5) from (6), we have
13v = 13 ⇒ v=1
Substituting the value, v = 1 in (v)
15u-6×1 = -3 ⇒ 15u=-3+6=3 ⇒u = 3/15=1/5
Now,
u = 1/(x+y)=1/5
⇒ x+y = 5....(vii)
v = 1/(x-y)=1
⇒ x-y=1....(viii)
Adding equation(vii) and equation(viii), we have
2x = 6
⇒ x = 3
Substituting the value of x in (vii), we get
3+y = 5
⇒ y = 5-3
= 2
Hence, the solution is x = 3, y = 2.
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