Solve 5cos2∅-2sin2∅=2
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Step-by-step explanation:
❤Changing to sine and factorizing, we have (sinθ+1)(5sinθ−3)=0. Since θ lies in the given interval, it must be -ive
∴sinθ=−1orθ= 2/3π = 4/6π
6π
6π which lies in the given interval.
6π which lies in the given interval.∴ 2θ = 4/3π and hence tan
2θ =tan 4/3π =−1❤
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