Question

Solve 5th part of question​

Answer 1

here we can see that BCFE is a trapezium

and in velocity time graph to find distance we find the area of the gigure formed

so the area of trapezium is 1/2×(BE+CF)×distance between them

here BC = 25 EF = 15

distance = 1

so area=1/2×(25+15)×1

1/2×40×1

20 m

it is your answer

hope it helps

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