solve 5th question imideatly plzz
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Given that one angle is 15° less than twice the second angle. So, if first angle is x then the other one = 2x - 15
We know that opposite angles are equal in a ||gm. So,the four angles would be
x, 2x - 15, x, 2x - 15
Now, the sum of angles of a ||gm is 360°
=> x + 2x - 15 + x + 2x - 15 = 360
=> 6x - 30 = 360
=> 6x = 360 + 30
=> 6x = 390
=> x = 390/6
=> x = 65°
So, other angle = 2(65) - 15
=> other angle = 130 - 15
=> other angle = 115°
So the angles are:-
65, 115, 65 and 115°
We know that opposite angles are equal in a ||gm. So,the four angles would be
x, 2x - 15, x, 2x - 15
Now, the sum of angles of a ||gm is 360°
=> x + 2x - 15 + x + 2x - 15 = 360
=> 6x - 30 = 360
=> 6x = 360 + 30
=> 6x = 390
=> x = 390/6
=> x = 65°
So, other angle = 2(65) - 15
=> other angle = 130 - 15
=> other angle = 115°
So the angles are:-
65, 115, 65 and 115°
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Let the smallest angle of the ||gm be x
Acc. To Ques
Another angle is 15 less than twice the smallest angle
so, the another angle = 2x - 15°
As we know that opp angles of a ||gm are equal so,
with reference to fig.
Angle ABC = Angle ADC=2x - 15
Angle BAD= angleBDC=x
So,
sum of all the angles of a ||gm = 360°
=>x + x + 2x - 15 + 2x - 15=360°
=>6x -30=360°
=>6x = 360°+30°
=>x= 390°/6
=>x = 65°
So, all the angles of the ||gm are
• 2x-15=2×65-25=105°
•x = 65°
Hence , all the angles are 65°,65°, 105, 105
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Hope It helps Uh !!....
.
:)
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