solve: (5x+1)/3 +1 = (x-5)/6
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Hi ,
( 5x + 1 )/3 + 1 = ( x - 5 ) /6
( 5x + 1 + 3 ) / 3 = ( x - 5 )/6
5x + 4 = ( 3 /6 ) ( x - 5 )
5x + 4 = ( 1/2)( x - 5 )
2 ( 5x + 4 ) = x - 5
10x + 8 = x - 5
10x - x = -8 - 5
9x = -13
x = -13 /9
I hope this helps you.
:)
or
(5x+1)/3 - (x-5 )/6 = -1
[2(5x+1)-(x-5)]/6= -1
10x+2 -x+5 = -6
9x +7 = -6
9x = -6-7
9x= -13
x = -13/9
verification :
put x = -13/9
LHS = ( 5x+1 )/3 + 1
= [ 5× (-13/9)+1]/3+1
= ( -65 /9 +1 )/3 + 1
= ( -65 + 9 )/(9×3 ) + 1
= -56 /27 +1
= ( -56 + 27 )/27
= -29/27
RHS = ( x - 5 )/6
= [ ( -13/9 ) - 5 ] /6
= ( -13 - 45 ) / ( 9× 6)
= - 58 / 54
= - 29/27
Therefore ,
LHS = RHS
( 5x + 1 )/3 + 1 = ( x - 5 ) /6
( 5x + 1 + 3 ) / 3 = ( x - 5 )/6
5x + 4 = ( 3 /6 ) ( x - 5 )
5x + 4 = ( 1/2)( x - 5 )
2 ( 5x + 4 ) = x - 5
10x + 8 = x - 5
10x - x = -8 - 5
9x = -13
x = -13 /9
I hope this helps you.
:)
or
(5x+1)/3 - (x-5 )/6 = -1
[2(5x+1)-(x-5)]/6= -1
10x+2 -x+5 = -6
9x +7 = -6
9x = -6-7
9x= -13
x = -13/9
verification :
put x = -13/9
LHS = ( 5x+1 )/3 + 1
= [ 5× (-13/9)+1]/3+1
= ( -65 /9 +1 )/3 + 1
= ( -65 + 9 )/(9×3 ) + 1
= -56 /27 +1
= ( -56 + 27 )/27
= -29/27
RHS = ( x - 5 )/6
= [ ( -13/9 ) - 5 ] /6
= ( -13 - 45 ) / ( 9× 6)
= - 58 / 54
= - 29/27
Therefore ,
LHS = RHS
kalika1:
check it by putting value of x on ur rough copy nd then send me the pic
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