Question

solve
(5x-2)/3 -(7x-3)/5 > x/4​

Answer 1

Hi baby

Hope this picture helps you

Brainiest answer please..

Answer 2

Answer:

Step-by-step explanation:

Given :

To find the set of values of x if,

$\frac{5x-2}{3} -(\frac{7x-3}{5} ) >\frac{x}{4}$

Solution :

$\frac{5x-2}{3} -(\frac{7x-3}{5} ) >\frac{x}{4}$

By bringing all variables to LHS , We get,

$\frac{5x-2}{3} -(\frac{7x-3}{5} ) -\frac{x}{4} >0$

$\frac{5x-2}{3} +\frac{-7x+3}{5}  -\frac{x}{4} >0$

By cross-multiplication, We get

$\frac{100x-40}{60} +\frac{-84x+36}{60} -\frac{15x}{60} >0$

$\frac{100x-40-84x+36-15x}{60} >0$

$\frac{x-4}{60} >0$

By multiplying 60 both the sides, we get

$x-4>0$×60

$x-4>0$

$x>4$

∴x∈(4,∞)