Math, asked by dhanyapmuhamad, 10 months ago

Solve 5x+3y-2=0,2x-y+7=0 in substitution method

Answers

Answered by Ravina
0

Answer:

x = -19/11, y = 39/11

Step-by-step explanation:

5x+3y-2=0 ...... Equation (1)

2x-y+7=0 ...... Equation (2)

Rearranging equation (2) we get,

2x+7=y ...... Equation (3)

Substituting equation (3) in equation (1), we get,

5x+3(2x+7)-2=0

5x+6x+21-2=0

11x+19=0

x = -19/11

Substituting x = -19/11 in equation (3), we get,

2(-19/11)+7=y

(-38/11)+7=y

(-38/11)+(7x11)/11=y

(-38+77)/11=y

39/11=y

y=39/11

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