Solve 5x+3y-2=0,2x-y+7=0 in substitution method
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Answer:
x = -19/11, y = 39/11
Step-by-step explanation:
5x+3y-2=0 ...... Equation (1)
2x-y+7=0 ...... Equation (2)
Rearranging equation (2) we get,
2x+7=y ...... Equation (3)
Substituting equation (3) in equation (1), we get,
5x+3(2x+7)-2=0
5x+6x+21-2=0
11x+19=0
x = -19/11
Substituting x = -19/11 in equation (3), we get,
2(-19/11)+7=y
(-38/11)+7=y
(-38/11)+(7x11)/11=y
(-38+77)/11=y
39/11=y
y=39/11
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