Question

solve 5x+3y=23 and 2x+4y=15 by elimination method

Answer 1

Given Equation is 5x + 3y = 23 ------- (1)

Given Equation is 2x + 4y = 15 ------- (2)

On solving (1) * 2 & (2) * 5, we get

10x + 6y = 46

10x + 20y = 75

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-14y = -29

y = 29/14.

Substitute y = 29/14 in (1), we get

= > 5x + 3y = 23

= > 5x + 3(29/14) = 23

= > 5x + 87/14 = 23

= > 5x = 23 - 87/14

= > 5x = 235/14

= > x = 47/14.

Therefore the value of x = 47/14 and y = 29/14.

Hope it helps!

Answer 2

SO,x = 29/14 and y = 47/14 ,✔✔

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