solve:5x-3y=8;3x+y=2 by substituting value of x
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5x-3y=8=
5x=3y+8
x=3y+8/5
3x+y=2=
3×3y+8/5 +y =2
9y+24/5 + y=2
9y+24+5y/5=2
14y+24/5=2
14y+24=10
14y=-14
- y= -1
3x+y=2
3x-1=2
3x=3
x=1
Hope it may be helpful to you.
krushnaivrathod:
Thank you very much sis. I needed it desperately. You helped me at the need.Thanks again
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bye!
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