Math, asked by anshshrivastava9742, 2 months ago

solve 5x+4y=10 and 3x-2y+16=0 and hence find the value of m for which y=mx+3​

Answers

Answered by vaishubh1707
13

Answer:

m = -1

Step-by-step explanation:

5x+4y-10 = 0----------1

3x-2y+16=0-------------2

After Multiplying equation 2 by 2 and then adding it from equation 1 we get,

5x+4y-10+6x-4y+32= 0

11x+22 = 0

11x = -22

x = - 2

3(-2) -2y +16 = 0 (from 2)

-6-2y+16 = 0

-2y = -10

y = 5

y = mx+ 3

5 = m(-2) +3

5-3= -2m

-2m=2

m = -1

Answered by sanjayrokhade761
2

Answer:

X = -2

Y = 5

M = -1

Please mark me as Brainlist Answer please

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