Question

Solve 5x+9=5+3x check your result and checking by Lhs and RHS

Answer 1

Answer:

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Answer 2

Question :

• 5x + 9 = 5 + 3x

Aim :

• To find the value of x and verify.

Solution :

5x + 9 = 5 + 3x

Transposing all the variables to one side, and constants to the other,

☞ 5x - 3x = 5 - 9

Subtracting,

☞ 2x = (-4)

Transposing 2 to the other side,

$\implies \sf x = \dfrac{ - 4}{2}$

Reducing to the lowest terms,

☞ x = (-2)

Therefore, x = (-2)

Verification :

By substituting the value for x as (-2) in the equation, let us verify the answer.

➜ 5(-2) + 9 = 5 + 3(-2)

➜ (-10) + 9 = 5 + (-6)

➜ (-1) = (-1)

LHS (LEFT HAND SIDE OF THE EQUATION) = RHS (RIGHT HAND SIDE OF THE EQUATION)

What are Variables and Constants?

Variables :

Variables are those terms which do not have a definite value. They change accordingly to satisfy the conditions of the equation. Variables are represented by alphabets such as a,x,k,y,z etc.

Constants :

Constants are those terms which have definite values. These values do not change. They include all the real numbers (rational and irrational numbers). Examples : 3,√10,3.4,11778966290.89637290,√π etc.

More to know :

• (+) × (+) = (+)
• (-) × (-) = (+)
• (-) × (+) = (-)
• (+) × (-) = (-)
• -(-) = (+)

$\bullet \: \sf {a}^{n} \times {a}^{m} = {a}^{n + m}$

$\bullet \: \sf {a}^{m} \div {a}^{} = {a}^{m - n}$

$\bullet \: \sf {a}^{ -m } = \dfrac{1}{ {a}^{m} }$

$\bullet \: \sf {a}^{m} \times {b}^{m} = {ab}^{m}$

$\bullet \: \sf {a}^{n} \div {b}^{n} = \bigg(\dfrac{a}{b} \bigg)^{n}$

$\bullet \: \sf {a}^{0} = 1$