solve ✓5x2-7x+✓20 by completing the square method
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√2 x² +7x +5 √2 = 0
⇒ √2 x² + 5x + 2x + 5√2 = 0
⇒ √2x² + 5x + √2*√2*x + 5√2=0
⇒ x(√2x + 5) + √2(√2x + 5) =0
⇒ (x+√2)(√2x+5) = 0
That gives x= - √2 or x= - 5/√2
⇒ √2 x² + 5x + 2x + 5√2 = 0
⇒ √2x² + 5x + √2*√2*x + 5√2=0
⇒ x(√2x + 5) + √2(√2x + 5) =0
⇒ (x+√2)(√2x+5) = 0
That gives x= - √2 or x= - 5/√2
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