Question

solve 5y^2-2y-2=0 plz solve this
quadratic equation
class 10
cbse board ​

Answer 1

Answer:

plzz see the attachment

Answer 2

The roots of the equation are 0.863 and -0.463.

Step-by-step explanation:

The quadratic equation is:

$5y^{2}-2y-2=0$

The roots of a quadratic equation are:

$y = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }$

Here,

a = 5

b = -2

c = -2

Compute the roots as follows:

$y = \frac{ -(-2) \pm \sqrt{(-2)^2 - 4(5)(-2)}}{ 2(5) }\\y = \frac{ 2 \pm \sqrt{4 - -40}}{ 10 }\\y= \frac{ 2 \pm \sqrt{44}}{ 10 }\\y = \frac{ 2 \pm 2\sqrt{11}\, }{ 10 }\\y = \frac{ 1}{ 5 } \pm \frac{ \sqrt{11}\, }{ 5 }\\y = 0.863325,\ -0.463325$

Thus, the roots of the equation are 0.863 and -0.463.

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