Solve 6 – 10[x + (2x – 3)] = –12x
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. x 2+5 x +6=0 ... 3x + 3 = x + 13, 3x = x + 10, 2x = 10, and x =
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=> 6 – 10[x + (2x – 3)] = –12x
=> 6 – 10[x + 2x – 3] = –12x
=> 6 – 10[3x – 3] = –12x
=> 6 – 10[3x] – 10[–3] = –12x
=> 6 – 30x + 30 = –12x
=> 36 – 30x = –12x
=> 6 – 5x = –2x
=> 6 = 5x – 2x
=> 6 = 3x
=> 2 = x
=> x = 2
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