Question

solve (6+√27)-(3+√3)+(1-2√3)​

Answer 1

Answer:

4

Step-by-step explanation:

$(6+\sqrt{27})-(3+\sqrt3)+(1-2\sqrt3)$

$=(6+\sqrt{3\times 3 \times 3})-(3+\sqrt3)+(1-2\sqrt3)$

$=(6+3\sqrt{3})-(3+\sqrt3)+(1-2\sqrt3)$

Opening brackets

$=6+3\sqrt{3}-3-\sqrt3+1-2\sqrt3$

$=6-3+1+3\sqrt3 -\sqrt 3 -2\sqrt 3$

$=4+3\sqrt3 -3\sqrt 3$

$=4$