Math, asked by MinnuAngel, 5 months ago

solve
6 + 2i /1 + i

Answers

Answered by ashishsharma1051

Answer:

6+2i/1+I ×1-i/1-i

4+8i/2

2+4i

MinnuAngel: is this answer 2-4i or 2+4i

MinnuAngel: please give an another answer

ashishsharma1051: its 2 + 4i

ashishsharma1051: do you want answer in detail ?

MinnuAngel: yes

ashishsharma1051: ok wait a sec..

MinnuAngel: ok

ashishsharma1051: 6 + 2I / 1 + i = 6+2i / 1 + I × 1 - I/ 1 - I = 6 + 6i +2i -2 / 2 = 4 + 8I / 2 = 2 + 4i

MinnuAngel: thank you

ashishsharma1051: N.P

Answered by mathdude500

$\begin{gathered}\Large{\bold{\pink{\underline{Formula \: Used \::}}}} \end{gathered}$

$\longrightarrow \:(1). \: \boxed{ \red{\tt \: {i}^{2} = - 1}}$

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$\large\underline\purple{\bold{Solution :- }}$

$\tt \: \longrightarrow \:\dfrac{6 + 2i}{1 + i}$

$\tt \: \longrightarrow \:\dfrac{6 + 2i}{1 + i} \times \dfrac{1 - i}{1 - i}$

$\tt \: \longrightarrow \:\dfrac{6 - 6i + 2i - {2i}^{2} }{ {1}^{2} - {i}^{2} }$

$\tt \: \longrightarrow \:\dfrac{6 - 4i + 2}{1 + 1}$

$\tt \: \longrightarrow \:\dfrac{8 - 4i}{2}$

$\tt \: \longrightarrow \:4 - 2i$

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