solve 6 and 7 fast urgent
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raunakjain30:
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6. Area = 160
smaller parallel side = 10cm
Longer side = 10 *3 = 30cm
Let the perpendicular distance be h
Area = 160
or, 1/2*h*(10+30) = 160
or, h = 8 cm.
The perpendicular distance is 8 cm.
7.Let the length of the sides be x and (x+3) cm.
Height = 18 cm
Area = 729
or, 1/2*18*(x+x+3) = 729
or,2x + 3 = 81
or,2x = 78
or, x = 39
The sides are 39 cm and 42 cm.
smaller parallel side = 10cm
Longer side = 10 *3 = 30cm
Let the perpendicular distance be h
Area = 160
or, 1/2*h*(10+30) = 160
or, h = 8 cm.
The perpendicular distance is 8 cm.
7.Let the length of the sides be x and (x+3) cm.
Height = 18 cm
Area = 729
or, 1/2*18*(x+x+3) = 729
or,2x + 3 = 81
or,2x = 78
or, x = 39
The sides are 39 cm and 42 cm.
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