Question

solve 6( log 2 with base x -log x with base 4)+7 =0​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

2 - log2(x2 + 3x)> 0 2>log2(x2 + 3x) 22≥(x2 + 3x) (x2 + 3x - 4 )0 x(x + 3)>0 x ϵ ( - ∞, - 3) (0,∞) Taking intersection, x ϵ [ - 4, - 3) (0,1 ]

I HOPE IT WILL HELP YOU

PLS MARK ME AS BRAINLIEST