Math, asked by sanjanaaveesam5791, 1 year ago

Solve: 6/x-1- 3/y-2=1, 5/x-1+1/y-2=2, where x is not 1 and y is not 2

Answers

Answered by MaheswariS
37

\text\bf{Given:}

\frac{6}{x-1}-\frac{3}{y-2}=1

\frac{5}{x-1}+\frac{1}{y-2}=2

\text{Take } u=\frac{1}{x-1}\;\&\; v=\frac{1}{y-2}

\text{We get ,}

6u-3v=1...........(1)

5u+v=2.............(2)

\textbf{solving (1) &(2)}

6u-3v=1...........(1)

 15+3v=6

21u=7

\implies\;u=\frac{7}{21}

\implies\;u=\frac{1}{3}

\text{put }u=\frac{1}{3}\text{ in (1) }we get}

6(\frac{1}{3})-3v=1

\implies\2-3v=1

\implies 3v=1

\implies\;v=\frac{1}{3}

\text{when }u=\frac{1}{3},

\frac{1}{3}=\frac{1}{x-1}

\implies\;x-1=3

\implies\bf\;x=4

\text{when }v=\frac{1}{3},

\frac{1}{3}=\frac{1}{y-2}

\implies\;y-2=3

\bf\;y=5

\therefore\textbf{The solution is x=4 and y=5}

Answered by Ikonikscenario7122
0

Answer: https://brainly.app.link/qpzV02MawO​

Step-by-step explanation:

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