Question

solve √6×x^2-4x-2√6=0​

Answer 1

Step-by-step explanation:

We have,

$\sqrt{6} {x}^{2} - 4x - 2 \sqrt{6} = 0$

$\implies \sqrt{6} {x}^{2} - 6x + 2x - 2 \sqrt{6} = 0$

$\implies \sqrt{6} x(x - \sqrt{6}) + 2(x - \sqrt{6} ) = 0$

$\implies(x - \sqrt{6} )( \sqrt{6}x + 2) = 0$

$\implies x = \sqrt{6} \: \: or \: \: x = - \frac{2}{ \sqrt{6} }$