Math, asked by aryandeshmukh9pd4kzl, 1 year ago

Solve.....
6-x/x^2-4 = 2 + x/x+2
 \frac{6-x}{x^2-4} = 2 +\frac{x}{x+2}
I need it urgent

Answers

Answered by paras18
1
(6-x)/(x*2-4) = 2 + x/(x+2)
(6-x)/(x+2)(x-2)=[2(x+2) + x]/(x+2)
(6-x)/(x-2)=3x+4
6-x = (3x+4)(x-2)
6-x = 3x*2-6x+4x-8
6-x = 3x*2-2x-8
3x*2-x-14 =0
3x*2-7x+6x-14=0
(3x-7)(x+2)=0
x=7/2 , -2
Answered by ad19052002
1

(6-x)/(x*2-4) = 2 + x/(x+2)

(6-x)/(x+2)(x-2)=[2(x+2) + x]/(x+2)

(6-x)/(x-2)=3x+4

6-x = (3x+4)(x-2)

6-x = 3x*2-6x+4x-8

6-x = 3x*2-2x-8

3x*2-x-14 =0

3x*2-7x+6x-14=0

(3x-7)(x+2)=0

x=7/3 , -2

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