Question

Solve (625/256)^3=(64/125)^2x-5
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Answer 1

Given,

(625/256)^3=(64/125)^2x-5

[(5/4)⁴]³= [(4/5)³]^(2x-5)

(5/4)^12= (4/5)^3(2x-5)

(4/5)^(-12)= (4/5)^3(2x-5)

Now equating power of (4/5) we get

-12= 3(2x-5)

=> 6x=15-12=3

=> x=3/6

=> x=1/2 Ans.