Question

solve..................

Answer 1

Heya mate, Here is ur answer

Given:∆is a right angled ∆ .

SO, Let angle A=90°

Let angle B=x°

A/Q

angle C=x-12°

Using sum angle property of a ∆

Angle A+Angle B+Angle C=180°

=>90°+x°+x°-12°=180°

=>78°+2x°=180

=>2x°=180°-78°

=>2x=102°

$= > x = \frac{102}{2}$

x=51°

So, Angle B=51 °

Angle C=51-12

=39°

Warm regards

@Laughterqueen

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