solve :6p-3q=1 and 5q+q=2
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Answer:
p=1/3 and q=1/3
Step-by-step explanation:
given, 5q+q=2
6q=2
q=2/6
q=1/3
substitute q in 6p-3q=1
6p-3(1/3)=1
6p-1=1
6p=1+1
6p=2
p=2/6
p=1/3.
REFER:
Substitute both p and q in 6p-3q=1
6(1/3)-3(1/3)=1
2-1=1
1=1
therefore LHS=RHS
hence proved
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