Question

solve 6sinsquare tita - cos tita -4=0​

Answer 1

Answer:

Θ = cos-1(4)

or cosΘ = 4

explanation

2sin²Θ = 1 - cos2Θ

cos2Θ = cos²Θ - sin²Θ

sin²Θ = 1 - cos²Θ

solution =

6sin²Θ - cosΘ - 4 = 0

3(2sin²Θ) - cosΘ - 4 = 0

3( 1 - cos2Θ ) - cosΘ - 4 = 0

3[ 1 - (cos²Θ - sin²Θ) ] - cosΘ - 4 = 0

3[ 1 - cos²Θ - ( 1 - cos²Θ ) ] - cosΘ - 4 = 0

3[ 1 - cos²Θ -1 + cos²Θ ] - cosΘ - 4 = 0

3(0) - cosΘ - 4 = 0

-cosΘ = 4

cosΘ = -4

Θ = cos`¹ ( -4 )

pls check it once is there any kind of mistake or not

hope this will help you

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