Question

Solve 6x+1+1÷3=x-3÷6

Answer 1

$6x+1+ \frac{1}{3} =x- \frac{3}{6} \\ 6x+ \frac{4}{3} = x- \frac{3}{6} \\ 5x = -( \frac{4}{3} + \frac{3}{6}) \\ 5x = -\frac{11}{6} \\ x=- \frac{11}{30}$

Answer 2

If the question was:
$6x+1+ \frac{1}{3} =x- \frac{3}{6}$
$6x+ \frac{4}{3} =x- \frac{1}{2}$
$6x-x= \frac{4}{3} + \frac{1}{2}$
$5x= \frac{8+3}{6}$
$x= \frac{11}{5*6} = \frac{11}{30} .$


If the question was:
$\frac{6x+1+1}{3}= \frac{x-3}{6}$
$2(6x+2)=x-6$
$12x-4=x-6$
$11x=2 and x= \frac{2}{11} .$