Question

solve 6x +1 upon 3 + 1 = x-3 upon 6​

Answer 1

please mark it as brainliest

Answer 2

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$\bf{To~solve:}$

$\bf \frac{6x + 1}{3} + 1 = \frac{x - 3}{6} \\ \\ \bf \frac{6x + 1 + 3}{3} = \frac{x - 3}{6} \\ \\ \bf \frac{6x + 4}{3} = \frac{x - 3}{6} \\ \\ \bf By \: cross \: multiplication, \: we \: get : \\ \\ \bf 6(6x + 4) = 3(x - 3) \\ \bf 36x + 24 = 3x - 9 \\ \bf 36x - 3x = - 9 - 24 \\ \bf 33x = - 33 \\ \bf x = \frac{ - 33}{33} = \underline{ \underline{- 1}}$

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