Math, asked by tanvi0123, 3 months ago

solve 6x^2-1=0 using formula​

Answers

Answered by samarjitomprakash23
0

Answer:

Step-by-step explanation:

=

±

2

4

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

6

2

1

=

0

6x^{2}-1=0

6x2−1=0

=

6

a={\color{#c92786}{6}}

a=6

=

0

b={\color{#e8710a}{0}}

b=0

=

1

c={\color{#129eaf}{-1}}

c=−1

=

0

±

0

2

4

6

(

1

)

2

6

Answered by wwwuamuam
12

6x^2 -1=0

6x^2 =1

x^2 =1/6

=)x =√1/6

=)x =+1/√6, -1/√6

x=1/√6 or -1/√6 is the answer

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