Question

solve 6x^2+x-1= 0
please answer stepwise​

Answer 1

Question:

= 6x² + x - 1 = 0

• Let's solve this equation using middle term splitting method.

= 6x² + 3x - 2x - 1 = 0

= 3x ( 2x + 1) - 1 ( 2x + 1 ) = 0

= (2x + 1 ) ( 3x - 1 ) = 0

Also, from here we have 2 solutions of x:

i) 2x + 1 = 0

= 2x = - 1

= x = -1/2

ii) 3x - 1 = 0

= 3x = 1

= x = 1/3

Done..!

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Answer 2

Answer:

$6x^2+x-1=0\quad :\quad x=\frac{1}{3},\:x=-\frac{1}{2}\quad \left(\mathrm{Decimal}:\quad x=0.33333\dots ,\:x=-0.5\right)$

Step-by-step explanation:

$6x^2+x-1=0$

$x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:6\left(-1\right)}}{2\cdot \:6}$

$x_{1,\:2}=\frac{-1\pm \:5}{2\cdot \:6}$

$x_1=\frac{-1+5}{2\cdot \:6},\:x_2=\frac{-1-5}{2\cdot \:6}$

$x=\frac{1}{3},\:x=-\frac{1}{2}$

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