solve (6x-3/x+4)^2 by taking reference from formula (a-b+c)^2
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Answer:
ok
using formulae.
(a-b+c)²=a²+b²+c²-2ab-2bc+2ca
= (6x)²+ (-3/x)²+(4)² -2*6x*3/x -2*3/x*4 +2*4*6x
=12x²+9/x²+16-36-24/x+48x
I hope this is correct
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