Question

Solve:
6x-55y=128
34x-15y=132
​

Answer 1

$x = \frac{128 + 55y}{6} \\ 34 \times \frac{128 + 55y}{6} - 15y = 132 \\ 17 \times \frac{128 + 55y}{3} - 15y = 132$

$\frac{2176 + 935y}{3} - 15y = 132 \\ \frac{2176 + 935y - 45y}{3} = 132$

$2176 + 890y = 396 \\ 890y = - 1780 \\ y = \frac{ - 1780}{890} = - 2$

$x = \frac{128 + 55y}{6} = \frac{128 - 110}{6} = \frac{18}{6} = 3$

$x = 3 \: \: \: \: \: \: \: \: y = - 2$