Question

Solve: 6x + 7 > 3x + 1
(i) x is integer and
(ii) x is real number
solve step by step​

Answer 1

explanation:

hope it'll help you☺

Answer 2

Answer:

(i) The solutions are $-1,0,1,2,...$ when $x$ is integer.

(ii) The solution set is $(-2,\infty)$ when $x$ is real number.

Step-by-step explanation:

Consider the given inequality as follows:

$6x+7 > 3x+1$ ...... (1)

⇒ $6x-3x+7 > 3x-3x+1$

⇒ $3x+7 > 1$

⇒ $3x+7-7 > 1-7$

⇒ $3x > -6$

⇒ $\frac{3x}{3} > -\frac{6}{3}$

⇒ $x > -2$

(i) When $x$ is an integer.

All integers greater than $-2$, i.e., $-1,0,1,2,...$ satisfies the inequality (1).

Therefore, the solution of the inequality $6x+7 > 3x+1$ are $-1,0,1,2,...$.

(ii) When $x$ is real number.

All real numbers which are greater than $-2$ satisfies the inequality (1).

Therefore, the solution set of the inequality $6x+7 > 3x+1$ is $(-2,\infty)$.

#SPJ3