solve: 6x²-35x +50=0
Answers
Answer:
STEP
1
:
Equation at the end of step 1
((2•3x2) - 35x) + 50
STEP
2
:
Trying to factor by splitting the middle term
2.1 Factoring 6x2-35x+50
The first term is, 6x2 its coefficient is 6 .
The middle term is, -35x its coefficient is -35 .
The last term, "the constant", is +50
Step-1 : Multiply the coefficient of the first term by the constant 6 • 50 = 300
Step-2 : Find two factors of 300 whose sum equals the coefficient of the middle term, which is -35 .
-300 + -1 = -301
-150 + -2 = -152
-100 + -3 = -103
-75 + -4 = -79
-60 + -5 = -65
-50 + -6 = -56
-30 + -10 = -40
-25 + -12 = -37
-20 + -15 = -35 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -20 and -15
6x2 - 20x - 15x - 50
Step-4 : Add up the first 2 terms, pulling out like factors :
2x • (3x-10)
Add up the last 2 terms, pulling out common factors :
5 • (3x-10)
Step-5 : Add up the four terms of step 4 :
(2x-5) • (3x-10)
Which is the desired factorization
final result : (3x - 10) . ( 2x - 5)