Question

Solve 6x²-x-15=0. Hence solve 6(y-3)²-(y-3)-15=0

Answer 1

Answer:

$6 {x}^{2} - x - 15 = 0$

$x = \frac{1 + - \sqrt{(1 + 360)} }{12}$

$x = \frac{1 + - 19}{12}$

$x = \frac{ - 3}{2} or \frac{5}{3}$

Now,

$y - 3 = \frac{ - 3}{2} or \frac{5}{3}$

$y - 3 = \frac{ - 3}{2}$

2y - 6 = -3

y = 3/2

y - 3 = 5/3

3y - 9 = 5

y = 14/3

y = 3/2 or 14/3

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