Question

Solve 7^1+x+7^1-x=50 for real x​

Answer 1

Answer:

2

Step-by-step explanation:

7^[1+x] + 7^[x-1] = 50 ⇒ 7^[1+x] + 7^[x-1] = 7^2 + 7^0

1+x = 2 x-1=0

x=2-1=1 x=1

sum of values of x= 1+1=2

Answer 2

Answer:

1

Step-by-step explanation:

$7^{1+x} + 7^{1-x} = 50\\7x^{1+x} + 7x^{1-x} = 49 +1\\\\7x^{1+x} + 7x^{1-x} = 7x^{2} +7x^{0}$

equating same powers

1+x = 2 , 1-x = 0

x = 1