Solve 7.18 +4.3 with regard to significant figures
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Answer:
(a) The given value is 0.007 \ m^2.
Since, the number is less than 1, the zeros on the right to the decimal before the first non-zero integer is insignificant. So, the number 7 is the only significant digit.
\therefore It has 1 significant digit.
(b) The value is 2.64 \times 10^{24} kg
For the determination of significant values, we do not consider the power of 10 (Number is not less than 1). The digits 2, 6, and 4 are significant figures.
\therefore It has 3 significant digits.
(c)The value is 0.2370 \ g cm^{-3}.
For the given value with decimals, all the numbers 2, 3, 7 and 0 are significant.
\therefore It has 4 significant digits.
(d) The value is 6.320 \ J.
It has 4 significant digits.
(e) The value is 6.032 \ Nm^{-2}.
All the four digits are significant as the zeros in between two non-zero values are also significant.
\therefore It has 4 significant digits.
(f) The value is 0.0006032 \ m^{2}
Same as (a), first three zeroes after the decimal is insignificant. Only 6, 0, 3, 2 are significant.
\therefore It has 4 significant digits.
Explanation:
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