Solve 7 + 2 (3x-1) = 17
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Answer:
Distribute
7
+
2
(
3
−
1
)
=
1
7
7
+
6
−
2
=
1
7
2
Subtract the numbers
7
+
6
−
2
=
1
7
5
+
6
=
1
7
3
Rearrange terms
5
+
6
=
1
7
6
+
5
=
1
7
4
Subtract
5
5
5
from both sides of the equation
6
+
5
=
1
7
6
+
5
−
5
=
1
7
−
5
5
Simplify
Subtract the numbers
Subtract the numbers
6
=
1
2
6
Divide both sides of the equation by the same term
6
=
1
2
6
6
=
1
2
6
7
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
2
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