Question

solve 7 sin square theta + 3 cos square theta is equal to 4​

Answer 1

Answer aduldu  hedldai cambou sorry thats my language

Step-by-step explanation:

Answer 2

Answer:

$\theta = n\pi + { - 1}^{n} ( \frac{\pi}{6})$

Step-by-step explanation:

$7 { \sin}^{2} \theta \: + 3 { \cos}^{2} \theta = 4 \\ \implies7 { \sin }^{2} \theta + 3(1 - { \sin }^{2} \theta) = 4 \\ \implies7 { \sin }^{2} \theta + 3 - 3 { \sin}^{2} \theta = 4 \\ \implies4 { \sin }^{2} \theta = 1 \\ \implies4 { \sin }^{2} \theta - 1 = 0 \\ \implies(2 \sin \theta + 1)(2 \sin \theta + 1) = 0 \\ \\ so \: we \: get \: \\ \sin \theta = - \frac{1}{2} \: \: and \: \: \sin \theta = \frac{1}{2} \\ \sin \theta = - \sin( \frac{\pi}{6} ) and \: \sin \theta = \sin \frac{\pi}{6} \\ \theta = \pi + \frac{\pi}{6} \: \: and \: \: \theta = \frac{\pi}{6} \\ therefore \: \theta = \frac{7\pi}{6} and \: \frac{\pi}{6}$