Solve
7(x + 2) + 3(y - 2) = 8
3(x - 2) + 7(y + 2) = 8
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Answer:
x = 0, y = 0
Step-by-step explanation:
7x + 14 + 3y - 6 = 8 => 7x + 3y + 8 = 8 => 7x + 3y = 8 - 8
=> 7x + 3y = 0 ------> 1st eq.
3x - 6 + 7y + 14 = 8 => 3x + 7y + 8 = 8 = 3x + 7y = 0 ----> 2nd eq.
Multiply 1st eq. with 3 and 2nd equation with 7
1st eq. ---> 21x + 9y = 0
2nd eq. ---> 21x + 49y = 0
Now subtract both the equations
21x + 9y = 0
-21x - 49y = 0
-----------------------
-40y = 0
-----------------------
40y = 0 => y = 0
Substitute y=0 in 1st eq.
=> 7x + 3(0) = 0
=> 7x = 0
= x = 0
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