Question

solve..?........?..........

Answer 1

Distance covered in nth second is given by
$u + \frac{a(2n - 1)}{2}$
so, 4+6n = u + a(2n-1)/2

putting n = 1st sec

10 = u + a/2

putting n = 2nd second

16 = u + a(3)/2
solving both will give u

U = 7m/s
A = 6m/s^2