solve 7cos^2theta + 3sin^2 theta =4
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7sin2x + 3cos2x = 4
So, 4sin2x + 3sin2x + 3cos2x = 4
4sin2x + 3 (sin2x + cos2x) = 4
4sin2x + 3(1) = 4
4sin2x = 4 – 3
4sin2x = 1
sin2x = ¼
sin x = ½
So, x = 30 degree.
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hope it will help u
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