Question

solve 7th question........

Answer 1

Heya!

If they can do work in 10,12 and 15 days..

Then we let that total work is LCM(10,12,15)
= 60 units..
So efficiency of A= 60/10=6
So efficiency of B= 60/12=5
so efficiency of C= 60/15=4

So work done By A=6/(6+5+4)
=6/15
By B=5/15
By C=4/15

And days took by them together to complete work= 60/(6+5+4)
=4 days..

Hope it Helps!