solve : 7x+5y=12 and 3x-2y =1 by subsitution method
Answers
Answer:
let the given system of equation is
7x+5y=12 (1)
3x-2y=1 (2)
From (1),we get y=(-7x/5) .....(3)
substituting y=(-7x/5) in (2),we get
3x-2 ×(-7x/5)=1
3x + 14x/5 =1
3x + 14x =1×5
17x =5
x=5/17
substituting the value of x in (3)
y=(-7x/5)
y=(-7 (5/17) /5)
y= -7/17
Answer:
hope the example will help you
Step-by-step explanation:
Sol. (i) We have,
x + y = 7 ….(1)
2x – 3y = 11 ….(2)
We shall eliminate x by substituting its value from one equation into the other. from equaton (1), we get
x + y = 7 ⇒ x = 7 – y
Substituting the value of x in equation (2), we get
2 × (7 – y) – 3y = 11
⇒ 14 – 2y – 3y = 11
⇒ –5y = – 3 or, y = 3/5
Now, substituting the value of y in equation (1), we get
x + 3/5 = 7 ⇒ x = 32/5.
Hence, x = 32/5 and y = 3/5