Question

solve 7x2+3x-4=0 by using the method completing square​

Answer 1

Answer:

7x2+3x-4=0

1-first of all multiply the first 7x2 and the last 4

7X2 ×(4)=28X2

2-then make conjugates of the 3x that multiply ti form 28X and after subtraction and addition form the 3X

7X2+7X-4X-4=0

3-then by using square

7X(X+1)-4(X+1)=0

(X+1)(7X-4)=0

(X+1)=0

(7X-4)=0

SO

X=-1

X=4/7