Solve :- 7y = -3y(square) - 4
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Answered by
25
7y+ 3y^2 +4 =0
3y^2 +7y+4 =0
3y^2 +4y+3y +4 =0
y (3y + 4) + 1 (3y+4)=0
(y+1) ( 3y+4) =0
y= -1 or y = -4/3
3y^2 +7y+4 =0
3y^2 +4y+3y +4 =0
y (3y + 4) + 1 (3y+4)=0
(y+1) ( 3y+4) =0
y= -1 or y = -4/3
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Answered by
7
Answer:
Step-by-step explanation:
7y = -3y²- 4
=>3y²+7y+4 = 0
=>3y²+3y+4y+4 = 0
=>3y(y+1)+4(y+1)=0
=> (3y+4)(y+1) = 0
Either (3y+4)= 0 or (y+1)=0
y=-4/3 y= -1
Step-by-step explanation:
7y = -3y²- 4
=>3y²+7y+4 = 0
=>3y²+3y+4y+4 = 0
=>3y(y+1)+4(y+1)=0
=> (3y+4)(y+1) = 0
Either (3y+4)= 0 or (y+1)=0
y=-4/3 y= -1
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