Solve
7y = minus 3y square minus 4
Answers
Answered by
0
7y=-3y^2-4
3y^2+7y+4=0
3y^2+3y+4y+4=0
3y(y+1)4(y+1)=0
(3y+4)(y+1)=0
y=-4รท3
y=-2
hope it helpzzz
plzz mark it as brainliest
Similar questions