Math, asked by veerdesai345, 3 months ago

Solve: 8+ 10(x-1) = 78​

Answers

Answered by ThatThinker
1

Answer:

8 + 10(x-1) = 78

=> 8 + 10x - 10 = 78

=> 8 - 10 + 10x = 78

=> -2 + 10x = 78

10x = 78 + 2

10x = 80

x = 80/10

x = 8

Answered by aryanshyadav511
0

Answer:

1

Distribute

8

+

1

0

(

1

)

=

7

8

8+{\color{#c92786}{10(x-1)}}=78

8+10(x−1)=78

8

+

1

0

1

0

=

7

8

8+{\color{#c92786}{10x-10}}=78

8+10x−10=78

2

Subtract the numbers

8

+

1

0

1

0

=

7

8

{\color{#c92786}{8}}+10x{\color{#c92786}{-10}}=78

8+10x−10=78

2

+

1

0

=

7

8

{\color{#c92786}{-2}}+10x=78

−2+10x=78

3

Rearrange terms

2

+

1

0

=

7

8

{\color{#c92786}{-2+10x}}=78

−2+10x=78

1

0

2

=

7

8

{\color{#c92786}{10x-2}}=78

10x−2=78

4

Add

2

2

2

to both sides of the equation

1

0

2

=

7

8

10x-2=78

10x−2=78

1

0

2

+

2

=

7

8

+

2

10x-2+{\color{#c92786}{2}}=78+{\color{#c92786}{2}}

10x−2+2=78+2

5

Simplify

Add the numbers

Add the numbers

1

0

=

8

0

10x=80

10x=80

6

Divide both sides of the equation by the same term

1

0

=

8

0

10x=80

10x=80

1

0

1

0

=

8

0

1

0

\frac{10x}{{\color{#c92786}{10}}}=\frac{80}{{\color{#c92786}{10}}}

1010x=1080

7

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

8

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